Question
Question: When the plane surface of a plano-convex lens of refractive index \[1.5\] is silvered, it behaves li...
When the plane surface of a plano-convex lens of refractive index 1.5 is silvered, it behaves like a concave mirror with f=30cm. When its convex surface is silvered, it will behave like a concave mirror of focal length:
& A.10cm \\\ & B.20cm \\\ & C.30cm \\\ & D.45cm \\\ \end{aligned}$$Solution
Here we have a plano-convex lens, which is being silvered on one side, that is either the plane side or the convex side is silvered. Clearly, if the lens is silvered, it acts as a mirror. Here, it is given that it will act as a concave mirror. Using the lens formula we can find focal length.
Formula used: fC1=(μ−1)R1
Complete step by step answer:
It is given that the refractive index plano-convex lens is 1.5.
First, when the plane side is silvered, we get a mirror with focal length f=30cm
Then the light ray gets refracted into the lens, gets reflected at the plane side and gets refracted again outside the lens.
We know that the power of plane mirror is PP=0 and the power of the curve surface be PC
Then the total power of the system is P=2PC−PP=2PC
We know f1=P
Then, fC2=301 where, fC is the focal length of the lens.
⟹fC=60
From lens makers formula we know that fC1=(μ−1)R1 where R is the radius of curvature of the lens. Substituting we get, 601=(1.5−1)R1
⟹R=30cm
The radius of the convex surface is 30cm.
Similarly, if the convex surface is silvered, then the P=2PC−PM=−PM, here PC=0 as it is silvered.
Then the fM1=−PM
Since the radius of the curvature of the plano-convex lens remains the same, we can say that fM=R=30
So, the correct answer is “Option C”.
Note: Thus for a plano-spherical mirror, the focal length is equal to the radius of the curvature of the mirror. Plano-spherical mirrors are used in adventure parks, as they produce different sizes of the images. Also a lens can be converted to a mirror by silvering one of its sides.