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Question

Physics Question on Wave optics

When the angle of incidence on a material is 60^{\circ}, the reflected light is completely polarized. The velocity of the refracted ray inside the material is (in ms1ms^{-1})

A

3×1083 \times 10^8

B

[32]×108\bigg[\frac{3}{\sqrt2}\bigg] \times 10^8

C

3×108\sqrt3 \times 10^8

D

0.5×1080.5 \times 10^8

Answer

3×108\sqrt3 \times 10^8

Explanation

Solution

From Brewster's law, μ=tanip\mu = tan \, i_p
cv=tan60=3\Rightarrow \frac{c}{v} = tan \, 60^\circ = \sqrt3
v=c3=3×1083\Rightarrow v = \frac{c}{\sqrt3} = \frac{3 \times 10^8}{\sqrt3}
=3×108ms1= \sqrt3 \times 10^8 \, ms^{-1}