Question

When ${\text{C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$is passed over red hot coke. It partially gets reduced to ${\text{CO}}\left( {\text{g}} \right)$. Upon passing ${\text{0}}{\text{.5L}}$of ${\text{C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$ over red hot coke. The total volume of the gases increased to ${\text{700mL}}$. The composition of the gaseous mixture at STP is
A.${\text{C}}{{\text{O}}_{\text{2}}}{\text{200mL;CO = 500mL}}$
B.${\text{C}}{{\text{O}}_{\text{2}}}{\text{ = 350mL;CO = 350mL}}$
C.${\text{C}}{{\text{O}}_{\text{2}}}{\text{ = 300mL;CO = 400mL}}$
D.${\text{C}}{{\text{O}}_{\text{2}}}{\text{ = 0}}{\text{.0 mL;CO = 700 mL}}$

Answer 1

We must have to know that in chemistry two main reactions play a major role. One is the oxidation reaction. Another is the reduction reaction. Oxidation reaction is nothing but addition of oxidation or removal of hydrogen or loss of electrons. Reduction is nothing but addition of hydrogen or removal of oxygen or gain of electrons in the reaction form reactant to product. For oxidation and reduction purposes using some reagents, reagents are called oxidising and reducing agents.
Formula used:
Litre is the unit of the liquid. The symbol of the litre is ${\text{L}}$. One litre is equal to a thousand millilitre.
${\text{L = 1000mL}}$
Complete step by step answer:
When ${\text{C}}{{\text{O}}_{\text{2}}}\left( {\text{g}} \right)$is passed over red hot coke. It partially gets reduced to ${\text{CO}}\left( {\text{g}} \right)$.
The molecular formula of carbon dioxide is ${\text{C}}{{\text{O}}_{\text{2}}}$ . The molecular formula of carbon monoxide is ${\text{CO}}$. Carbon dioxide is reduced to carbon monoxide due to the loss of oxygen by red hot coke.
The reaction for the above discussion given below,
${\text{C}}{{\text{O}}_{\text{2}}}{\text{ + C}} \to {\text{2CO}}$
The given data,
The initial volume of carbon dioxide ${\text{C}}{{\text{O}}_{\text{2}}}$ is ${\text{0}}{\text{.5L}}$.
We convert the volume in millilitre because, same unit is required for the calculation.
One litre is equal to a thousand millilitre.
${\text{L = 1000mL}}$
The calculation for ${\text{0}}{\text{.5L}}$ is
${\text{ = 0}}{\text{.5L}}$
${\text{ = 0}}{\text{.5}} \times {\text{1000}}$
${\text{ = 500mL}}$
The final volume of total gas is ${\text{700mL}}$.
The final volume of carbon dioxide ${\text{C}}{{\text{O}}_{\text{2}}}$ is ${\text{500ml - x}}$.
The final volume of carbon monoxide${\text{CO}}$ is ${\text{2x}}$.
${\text{C}}{{\text{O}}_{\text{2}}}{\text{ + C}} \to {\text{2CO}}$
According to the above reaction we calculated as,
${\text{(500ml - x) + 2x = 700ml}}$
${\text{500ml + x = 700ml}}$
${\text{x = 700ml - 500ml}}$
${\text{x = 200ml}}$
We consider x volume of carbon dioxide ${\text{C}}{{\text{O}}_{\text{2}}}$ partially gets reduced to carbon monoxide${\text{CO}}\left( {\text{g}} \right)$ by red hot coke.
The final volume of carbon dioxide ${\text{C}}{{\text{O}}_{\text{2}}}$ is calculated as,
${\text{ = 500ml - x}}$
${\text{ = 500ml - 200ml}}$
${\text{ = 300ml}}$
The final volume of carbon monoxide ${\text{CO}}$ is calculated as,
${\text{ = 2x}}$
${\text{ = 2}} \times {\text{200ml}}$
${\text{ = }}4{\text{00ml}}$
According to the above calculation we conclude, the final volume of carbon dioxide ${\text{C}}{{\text{O}}_{\text{2}}}$ and carbon monoxide ${\text{CO}}$ is ${\text{C}}{{\text{O}}_{\text{2}}}{\text{ = 300mL and CO = 400mL}}$.

Hence, option C is correct. Because option C is correct only having ${\text{C}}{{\text{O}}_{\text{2}}}{\text{ = 300mL and CO = 400mL}}$.

Note:
The carbon dioxide is one of the gases used for cooling the reaction. If one reaction carbon dioxide evolves means that reaction is considered an endothermic reaction. Air is one of the important things in our life. In the world, without air nothing is surveyed. For human beings, breathing purpose air is the important thing for inhaling and exhaling. For human respiration, oxygen is used for inhalation of breathing and carbon dioxide is exhaled gas.