Question
Question: When \[{\text{262 g}}\] of xenon (atomic mass = 131) reacted completely with \[{\text{152 g}}\] of f...
When 262 g of xenon (atomic mass = 131) reacted completely with 152 g of fluorine (atomic mass = 19), a mixture of XeF2 and XeF6 was produced. The molar ratio XeF2 : XeF6 is :
A 1 : 2
B 1 : 4
C 1 : 1
D 1 : 3
Solution
Apply POAC. According to POAC, the number of moles (or mass) of a particular element in the reactants is equal to its number of moles (or mass) in products.
Complete answer:
Xenon is a noble gas. It is chemically unreactive as it has completed its octet. However, it does form some compounds especially with fluorine. Thus, xenon reacts with fluorine to form compounds such as xenon difluoride and xenon hexafluoride.
Xe + n F2→XeF2+XeF6
Calculate the number of moles for 262 g of xenon (atomic mass = 131)
131262=2
The molecular weight of fluorine is 38.
2×19=38
Calculate the number of moles of fluorine present in 152 g
38152=4
Let the number of moles of XeF2 and XeF6formed be ‘a’ and ‘b’ respectively.
Apply POAC
a×1+b×1=2 … …(1)
⇒2a+6b=8 … …(2)
Rearrange equation (1)
⇒b=2−a… …(3)
Substitute equation (3) in equation (2)
2a+6b=8
⇒2a+6(2−a)=8
⇒2a−6a+12=8
⇒4a=4
⇒a=1 … …(4)
Substitute equation (4) in equation (3) and calculate b,
b=2−a
⇒b=2−1
⇒b=1
The molar ratio XeF2 : XeF6 is 1:1.
So the option (C) is the correct option.
Note: POAC is the principle of atom conservation. This principle will help you in solving chemical equations. IF you apply this principle, then you do not need to balance the chemical equations. POAC is based on the conservation of mass.