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Question

Question: When \(\tan x = 0\), what does \(x\) equal?...

When tanx=0\tan x = 0, what does xx equal?

Explanation

Solution

Hint : In this question we have to find the value of xx or we can say that we have to find the general solution of the given expression. Here we will use the fact of the general solution of the trigonometric expression i.e. we know that when there is tanx=tany\tan x = \tan y ,then the general solution is given by x=nπ+y,nZx = n\pi + y,n \in Z , where nn is an integer.
So we will use this property to solve this question.

Complete step-by-step answer :
As per the question we have the expression tanx=0\tan x = 0.
Now we know the general solution of the tangent equation i.e. tanx=tany\tan x = \tan y , is given by x=nπ+y,nZx = n\pi + y,n \in Z .
So we can write the expression as
tanx=tan0\Rightarrow \tan x = \tan 0
By comparing the question with the formula, we have
x=x,y=0\Rightarrow x = x,y = 0
We will apply the formula, and it can be written as
x=nπ+0\Rightarrow x = n\pi + 0
Hence the required value of xx is nπn\pi for some integer nn .
So, the correct answer is “ nπn\pi ”.

Note : We should always remember these formulas to solve the question. There is also another formula which says that if we have tan2x=a,a>0{\tan ^2}x = a,a > 0 , then the general solution is given by x=nπ±arctan(a)x = n\pi \pm \arctan \left( {\sqrt a } \right) . Similarly the general solution of the equation sin2x=a,a(0,1]{\sin ^2}x = a,a \in (0,1] , is given by x=nπ+arcsin(a)x = n\pi + \arcsin (a) .