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Question: When sodium reacts with excess of oxygen, the oxidation number of oxygen changes from....

When sodium reacts with excess of oxygen, the oxidation number of oxygen changes from.

A

0 to -1

B

0 to -2

C

-1 to -2

D

No change.

Answer

0 to -1

Explanation

Solution

: 2Na+O20→Na2O2−12 \mathrm { Na } + \mathrm { O } _ { 2 } ^ { 0 } \rightarrow \mathrm { Na } _ { 2 } \mathrm { O } _ { 2 } ^ { - 1 }