Question

When sodium nitrate is heated above $\text{600}{{\,}^{\text{o}}}\text{C,}$ then:

• A. only $\text{N}{{\text{a}}_{\text{2}}}\text{O}$ is formed
• B. only ${{\text{N}}_{2}}$ is formed
• C. only ${{\text{O}}_{\text{2}}}$ is formed
• D. all are formed

Answer 1

Answer: (D)

all are formed

Answer 2

On heating $\text{NaN}{{\text{O}}_{\text{3}}}$ above $\text{600}{{\,}^{\text{o}}}\text{C}\,\text{N}{{\text{a}}_{\text{2}}}\text{O,}\,{{\text{O}}_{\text{2}}}$ and ${{\text{N}}_{2}}$ all is obtained as: $4NaN{{O}_{3}}\xrightarrow{800{{\,}^{o}}C}2N{{a}_{2}}O+5{{O}_{2}}+2{{N}_{2}}$