Question

When $SO_{2}$ is passed through acidified $K_{2}Cr_{2}O_{7}$ solution .

• A. The solution turns blue
• B. The solution is decolourised
• C. $SO_{2}$ is reduced
• D. Green $Cr_{2}(SO_{4})_{3}$ is formed

Answer 1

Answer: (D)

Green $Cr_{2}(SO_{4})_{3}$ is formed

Answer 2

$K_{2}Cr_{2}O_{7} + H_{2}SO_{4} + 3SO_{2} \rightarrow$

$K_{2}SO_{4} + \underset{\text{Green}}{Cr_{2}(SO_{4})_{3}} + 3H_{2}O$