Question

When plate voltage in diode valve is increased from 100 volt to 150 volt then plate current increases from 7.5 mA to 12 mA. The dynamic plastic resistance will be

• A. 10 kΩ
• B. 11 kΩ
• C. 15 kΩ
• D. 11.1 kΩ

Answer 1

Answer: (D)

11.1 kΩ

Answer 2

$r_{p} = \frac{\Delta V_{p}}{\Delta i_{p}} = \frac{150 - 100}{(12 - 7.5) \times 10^{- 3}} = \frac{50}{4.5} \times 10^{3} = 11.1k\Omega$.