Question

When oxygen is passed through silent electric discharge, it is 10% converted to ozone.
$3{O_2}\left( g \right) \rightleftharpoons 2{O_3}\left( g \right)$
What volume of ${O_3}$ will be formed by using 30 litres of ${O_2}$?

Answer 1

Hint: We will first deduce some simple facts from the given balanced equation and then solve it further. We will also find out 10% of 30 litres as per asked by the question in order to get our final answer.

Complete step by step solution:

The balanced equation given to us by the question is-
$3{O_2}\left( g \right) \rightleftharpoons 2{O_3}\left( g \right)$
- From this it is clear that three moles of ${O_2}$ is equivalent to two moles of ${O_3}$.
- It can thus be derived from the equation above that three litres of oxygen will give us 2 litres of ozone.
But it is given in the question that the particular amount of oxygen taken by us for the reaction, only 10% of it is converted to ozone.
So, if we take 30 litres of oxygen, the amount of ozone will be-
3 litres of oxygen will give us 2 litres of ozone.
30 litres of oxygen will give us-$\dfrac{{30 \times 2}}{3} = 20litres$ of ozone.
- But it was said that only 10% gets converted into ozone. That means 10% of 30 litres will be-
$\Rightarrow \dfrac{{10}}{{100}} \times 30 \\\ \\\ \Rightarrow 3litres \\\$

Thus, the volume of the ozone obtained by 30 litres of oxygen is 2 litres.

Note: A sparkless or silent electrical discharge is essential for the reaction to create less heat because ozone becomes expected to dissociate into oxygen and the temperature becomes raised (Le Châtelier 's principle). Therefore, ozone is formulated to promote the above conditions in a specifically built system named ozonizer. An 'Ozonizer' is the ozone collection system used to clean ozone through silent electricity. The Siemen's and the Brodie Ozonizers are two forms of ozonizers.