Question

When one mole of each of the following complexes is treated with excess $AgNO_{3},$ which will give maximum amount of AgCl?

• A. $\lbrack Co(NH_{3})_{6}\rbrack Cl_{3}$
• B. $\lbrack Co(NH_{3})_{5}Cl\rbrack Cl_{2}$
• C. $\lbrack Co(NH_{3})_{4}Cl_{2}\rbrack Cl$
• D. $\lbrack Co(NH_{3})_{3}Cl_{3}\rbrack$

Answer 1

Answer: (A)

$\lbrack Co(NH_{3})_{6}\rbrack Cl_{3}$

Answer 2

$\lbrack Co(NH_{3})_{6}\rbrack Cl_{3}$given 3 moles of AgCl.

$\lbrack Co(NH_{3})_{5}Cl\rbrack Cl_{2}$give 2 moles of AgCl.

$\lbrack Co(NH_{3})_{4}Cl\rbrack$ gives 1 mole of AgCl.

$\lbrack Co(NH_{3})_{3}Cl_{3}\rbrack$ Will not give AgCl.