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Question: When nothing is placed between jaws of a verniercallipers of MSD = 1 mm then sixth vernier scale div...

When nothing is placed between jaws of a verniercallipers of MSD = 1 mm then sixth vernier scale division coincides with a main scale division and zero of main scale is on left of zero of vernier scale. Calculate zero error if 9 main scale divisions equals 10 vernier scale divisions –

A

– 0.6 mm

B
  • 0.6 mm
C

– 0.4 mm

D
  • 0.4 mm
Answer
  • 0.6 mm
Explanation

Solution

LC = 110\frac { 1 } { 10 } = 0.1 mm

zero error = + 6 × 0.1 = + 0.6 mm