Question

“When mixture of $N{{H}_{4}}Cl$ and $NaN{{O}_{2}}$ is heated, gaseous product formed is ${{N}_{2}}$”.
Answer whether the above statement is true or false.

Answer 1

The answer to this question is based on the reaction of ammonium chloride with the sodium nitrite and the balanced reaction that yields the product will make you find the answer easily.

Complete answer:
In the lower classes of chemistry, we have studied about balancing a chemical equation and also about the concepts that deal with the writing of equations when reactants are given.
Now let us see what is the product formed when a mixture of ammonium chloride and sodium nitrite is reacted to.
- Ammonium chloride is a white crystalline salt that is highly soluble in water and these solutions of ammonium chloride are mildly acidic.
- Sodium nitrite on the other hand is also a salt which is white crystalline powder which is very soluble in water and also hygroscopic in nature. This is the most important nitrite salt in industrial processes.
When the aqueous solution of these two compounds that is ammonium chloride and sodium nitrite are made to react with each other then the product formed is as shown below,
$N{{H}_{4}}Cl(aq)+NaN{{O}_{2}}\to {{N}_{2}}(g)+2{{H}_{2}}O(l)+NaCl(aq)$
Therefore, it can be seen that one mole of each of these solids in aqueous forms yield one mole of nitrogen gas.

Therefore, the given statement is true.

Note: Do not be confused between sodium nitrate and sodium nitrite when the questions are given in the names and not in the form of the molecular formula. Sodium nitrite has the formula$NaN{{O}_{2}}$and sodium nitrate on the other hand has the formula where there is one extra oxygen atom that is $NaN{{O}_{3}}$.