Question

When $KMnO_{4}$is reduced with oxalic acid in acidic solution, the oxidation number of Mn changes from.

• A. +2 to 7
• B. +4 to +7
• C. +7 to +2
• D. +6 to +2

Answer 1

Answer: (C)

+7 to +2

Answer 2

:

$MnO_{4}^{-} = x + 4( - 2) = - 1 \Rightarrow x = + 7$

$Mn^{2 +} = + 2$