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Question: When iron is added to \(CuS{O_4}\)solution, copper is precipitated . It is due to : A.oxidation of...

When iron is added to CuSO4CuS{O_4}solution, copper is precipitated . It is due to :
A.oxidation of Cu+2C{u^{ + 2}}
B.reduction of Cu+2C{u^{ + 2}}
C.hydrolysis of CuSO4CuS{O_4}
D.ionization of CuSO4CuS{O_4}

Explanation

Solution

We know that when iron is added in CuSO4CuS{O_4}solution , copper is precipitated . The reaction between iron and CuSO4CuS{O_4}is an example of redox reaction . That is it undergoes both oxidation and reduction reaction simultaneously .

Complete step by step solution:
The chemical reaction between CuSO4CuS{O_4}solution and iron can be written as : Fe+CuSO4Fe(SO4)+CuFe + CuS{O_4} \to Fe(S{O_4}) + Cu. Now we will write the chemical reaction by denoting their respective oxidation states: Fe0+CuIISO4FeII(SO4)+Cu0F{e^0} + C{u^{II}}SO{}_4 \to F{e^{II}}(S{O_4}) + C{u^0}. We can observe that The oxidation number of FeFe is changing from 00 to 22. The oxidation number is increasing , that means it is undergoing oxidation. Similarly the oxidation state of CuCu is changing from 22 to 00. The oxidation number is decreasing , that means Cu+2C{u^{ + 2}} is undergoing a reduction reaction.

Hence, option: B. reduction of Cu+2C{u^{ + 2}} is correct.**

Additional information: CuSO4CuS{O_4} is also known as blue vitriol (pentahydrate).In the reaction Fe+CuSO4Fe(SO4)+CuFe + CuS{O_4} \to Fe(S{O_4}) + Cu ,CuSO4CuS{O_4} is an oxidising agent and FeFeis a reducing agent. CuSO4CuS{O_4} can kill bacteria, algae, roots, plants ,snails and fungi. Copper sulphate can be toxic. The toxicity depends on the copper content. The anhydrous copper sulphate is greenish white in colour .The pentahydrate form is blue in colour. The density of anhydrous copper sulphate is 3.60g/cm33.60g/c{m^3}. An anhydrous compound does not contain water molecules attached to it.

Note:
Always remember that whenever iron is added to CuSO4CuS{O_4} solution, the reaction we will observe is Fe0+CuIISO4FeII(SO4)+Cu0F{e^0} + C{u^{II}}SO{}_4 \to F{e^{II}}(S{O_4}) + C{u^0}. Copper ions get reduced and get precipitated. The iron gets oxidised from FeFeto FeIIF{e^{II}}.In this reaction CuSO4CuS{O_4}is an oxidising agent and FeFe is a reducing agent.