Question

When $H_2$ and $I_2$ are mixed and equilibrium is attained, then

• A. amount of HI formed is equal to the amount of $H_2$ dissociated
• B. HI dissociation stops
• C. the reaction stops completely
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

$(a)\, H_2 + I_2 \rightarrow 2HI$ $\therefore$ 1 mole of $H_2$ gives 2 moles of H1. $(b)$ At equilibrium the backward and forward reactions do not stop. $(c)$ The reaction does not stop but $R_f = R_b$.