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Question: When glycerol is heated with \(\mathrm { KHSO } _ { 4 }\) it gives...

When glycerol is heated with KHSO4\mathrm { KHSO } _ { 4 } it gives

A

CH2=CH−CH3\mathrm { CH } _ { 2 } = \mathrm { CH } - \mathrm { CH } _ { 3 }

B

CH2=CH−CH2OH\mathrm { CH } _ { 2 } = \mathrm { CH } - \mathrm { CH } _ { 2 } \mathrm { OH }

C

CH2=CH−CHO\mathrm { CH } _ { 2 } = \mathrm { CH } - \mathrm { CHO }

D

Answer

CH2=CH−CHO\mathrm { CH } _ { 2 } = \mathrm { CH } - \mathrm { CHO }

Explanation

Solution

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