Question

When $Fe _{0.93} O$ is heated in presence of oxygen, it converts to $Fe _2 O _3$ The number of correct statement/s from the following is
A. The equivalent weight of $Fe _{093} O$ is Molecular wejght $0.79$
B. The number of moles of $Fe ^{2+}$ and $Fe ^{3+}$ in 1 mole of $Fe _{0.93} O$ is $0.79$ and $014$ respectively
C. $Fe _{0.93} O$ is metal deficient with lattice comprising of cubic closed packed arrangement of $O ^{2-}$ ions
D. The $\%$ composition of $Fe ^{2+}$ and $Fe ^{3+}$ in $Fe _{093} O$ is $85 \%$ and $15 \%$ respectively

Answer 1

The correct answer is 4.
A : Fe0.93​O→Fe2​O3​
nf=(3−93200​)×0.93
nf=0.79
B: 2x+(0.93−x)×3=2
x=0.79
Fe2+=0.79,Fe3+=0.21
C : Fact
D : %Fe2+=0.930.79​×100=85%;Fe3+=15%