Question
Question: When excess of ethyl iodide is treated with ammonia, the product is....
When excess of ethyl iodide is treated with ammonia, the product is.
A
Ethylamine
B
Diethylamine
C
Triethylamine
D
Tetraethylammonium iodide.
Answer
Tetraethylammonium iodide.
Explanation
Solution
: NH3+(Excess)C2H5I→Quaternarysalt[(C2H5)4N+]I−