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Question: When ethylene bromide is treated with \(Zn,\) we get....

When ethylene bromide is treated with Zn,Zn, we get.

A

Alkane

B

Alkene

C

Alkyne

D

All

Answer

Alkene

Explanation

Solution

CH2∣Br−CH2∣Br+Zn→CH2=CH2Alkene+Br2\underset{\underset{Br}{|}}{CH_{2}} - \underset{\underset{Br}{|}}{CH_{2}} + Zn \rightarrow \underset{\text{Alkene}}{CH_{2} = CH_{2}} + Br_{2}