Question

When ethyl iodide is heated with silver nitrate, the product obtained is.

• A. $C_{2}H_{5}Ag$
• B. $Ag - O - NO_{2}$
• C. $C_{2}H_{5}O - NO_{2}$
• D. $C_{2}H_{5}I - NO_{2}$

Answer 1

Answer: (C)

$C_{2}H_{5}O - NO_{2}$

Answer 2

$C_{2}H_{5} - I + AgNO_{3} \rightarrow C_{2}H_{5}ONO_{2} + AgI$