Question

When ethyl alcohol$(C_{2}H_{5}OH)$ reacts with thionyl chloride, in the presence of pyridine, the product obtained is.

• A. $CH_{3}CH_{2}Cl + HCl$
• B. $C_{2}H_{5}Cl + HCl + SO_{2}$
• C. $CH_{3}CH_{2}Cl + H_{2}O + SO_{2}$
• D. $CH_{3}CH_{2}Cl + HCl + SO_{2}$

Answer 1

Answer: (D)

$CH_{3}CH_{2}Cl + HCl + SO_{2}$

Answer 2

$C_{2}H_{5}OH + SOCl_{2}\overset{\quad\text{Pyridine}\quad}{\rightarrow}C_{2}H_{5}Cl + SO_{2} + HCl$