Question

When ethanol and acetic acid are mixed together in equimolar proportions, equilibrium is attained when 2/3rd of acid and alcohol are consumed. The equilibrium constant for the reaction is

• A. 0.4
• B. 40
• C. $4 \times 10^2$
• D. $4 \times 10^0$

Answer 1

Answer: (D)

$4 \times 10^0$

Answer 2

$\underset{\text{1 mol 1/3 mol}}{{CH_{3}COOH}}$ + $\underset{\text{ 1 mol 1/3mol}}{{C_{2}H_{5}OH}}$ ${\rightleftharpoons}$ $\underset{\text{2/3 mol}}{CH_{3}COOC_{2}H_{5}} + \underset{\text{2/3mol}}{H_{2}O}$ $K=\frac{2/3\times 2/3}{1/3\times}{1/3}=4$