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Question: When electricity is passed through the solution of \(AlCl_{3},\) 13.5 gm of Al are deposited. The nu...

When electricity is passed through the solution of AlCl3,AlCl_{3}, 13.5 gm of Al are deposited. The number of Faraday must be

A

0.50

B

1.00

C

1.50

D

2.00

Answer

1.50

Explanation

Solution

Eq. of Al=13.527/3=1.5= \frac{13.5}{27/3} = 1.5; Thus 1.5 Faraday is needed.