Question

When dihydroxy acetone reacts with $HI0_4$, the product is/are

• A. HCHO
• B. HCOOH
• C. HCHO and HCOOH
• D. HCHO and $\text{C}{{\text{O}}_{2}}$

Answer 1

Answer: (D)

HCHO and $\text{C}{{\text{O}}_{2}}$

Answer 2

$\underset{C{{H}_{2}}OH}{\overset{C{{H}_{2}}OH}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,=O\xrightarrow{HI{{O}_{4}}}2HCHO+C{{O}_{2}}$