Question

When current in a coil changes to 2 ampere from 8 ampere in , the e.m.f. induced in the coil is 2 volt. The self inductance of the coil in millihenry is

• A. 1
• B. 5
• C. 20
• D. 10

Answer 1

Answer: (A)

1

Answer 2

$e = L \frac { d i } { d t }$ ⇒$2 = L \times \frac { 6 } { 3 \times 10 ^ { - 3 } } \Rightarrow L = 1 \mathrm { mH }$