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Question

Physics Question on Electromagnetic induction

When current in a coil changes from 5A5 \,A to 2A2 \,A in 0.1s0.1\, s, an average voltage of 50V50\, V is produced. The self - inductance of the coil is :

A

0.67 H

B

1.67 H

C

3 H

D

6 H

Answer

1.67 H

Explanation

Solution

According to Faraday?s law of electromagnetic induction,
Induced emf, e=Ldidte =\frac{Ldi}{dt}
50=L(520.1sec)50 = L\left(\frac{5-2}{0.1\,sec}\right)
L=50×0.13=53=1.67H\Rightarrow L = \frac{50\times0.1}{3} = \frac{5}{3} = 1.67\, H