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Question: When chloroform reacts with ethyl amine in presence of alcoholic KOH, the compound formed is...

When chloroform reacts with ethyl amine in presence of alcoholic KOH, the compound formed is

A

Ethyl cyanide

B

Ethyl isocyanide

C

Formic acid

D

An amide

Answer

Ethyl isocyanide

Explanation

Solution

CHCl3+C2H5NH2+3KOHCHCl_{3} + C_{2}H_{5}NH_{2} + 3KOH \rightarrow

C2H5N=CEthylisocyanide+3KCl+3H2O\underset{\text{Ethylisocyanide}}{C_{2}H_{5}N\overrightarrow{=}C} + 3KCl + 3H_{2}O