When calomel reacts with (NH\_{4}OH,) we get. | CHEMISTRY - SOME IMPORTANT COMPOUNDS OF TRANSITION ELEMENTS | SolveeIt

When calomel reacts with $NH_{4}OH,$ we get.

$HgNH_{2}Cl$

$NH_{2} - Hg - Hg - Cl$

$Hg_{2}O$

$HgO$

Answer

$HgNH_{2}Cl$

Explanation

$\underset{\text{Calomal}}{Hg_{2}Cl_{2}} + 2NH_{4}OH \rightarrow NH_{4}Cl + 2H_{2}O + Hg + HgNH_{2}Cl$

Question: When calomel reacts with \(NH_{4}OH,\) we get....