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Chemistry Question on d block elements

When 'blue vitriol' is heated at 373 K373 \,K, the product formed is

A

CuSO4.3H2OCuSO_{4}.3H_{2}O

B

CuO+SO3CuO+SO_{3}

C

CuSO4.H2OCuSO_{4}.H_{2}O

D

CuSO4CuSO_{4}

Answer

CuSO4.H2OCuSO_{4}.H_{2}O

Explanation

Solution

CuSO4.5H2Oblue vitriol→−4H2O373 KCuSO4.H2Obluish white→−H2O503 K\underset{\text{blue vitriol}}{CuSO_4.5H_2O} \xrightarrow[-4H_2O]{373\,K} \underset{\text{bluish white}}{CuSO_4 . H_2O} \xrightarrow[-H_2O]{503\,K}
CuSO4white→1023 KCuO+SO2+O2⏟SO3\underset{\text{white}}{CuSO_4} \xrightarrow{1023\,K} CuO + \underbrace{SO_2 + O_2}_{SO_3}