Question

When benzene sulphuric acid and p-nitro phenol react with $NaHC{O_3}$ , the gases released respectively are?
A. $S{O_2},N{O_2}$
B. $S{O_2},NO$
C. $S{O_2},C{O_2}$
D. $C{O_2},C{O_2}$

Answer 1

Sodium bicarbonate is a crystalline white solid, but can be seen in fine powder form. It is a chemical compound with a molecular formula of $NaHC{O_3}$ . It is composed of sodium cations and bicarbonate anion.

Complete answer: Sodium bicarbonate is generally known as baking soda, as it acts as an antacid.
Sodium bi carbonate reacts with benzene sulphuric acid and p-nitrophenol differently but they produce the same gas as a by-product.
So, let’s have a look separately at the chemical reaction of the two species when reacting with sodium by carbonate.
Coming to first one: when benzene sulphuric acid is treated with sodium bi carbonate, $NaHC{O_3}$
And the reaction is: $PhS{O_3}H + NaHC{O_3} \to PhS{O_3}Na + C{O_2} + {H_2}O$
Thus, we can see that, when benzene sulphuric acid is treated with sodium bi carbonate, $NaHC{O_3}$ , the carbon dioxide gas, $C{O_2}$ is released.
Now, Coming to our next reaction and solving it , i.e. when p-nitrophenol reacts with$NaHC{O_3}$.
The chemical equation is: $p - {N_2}O - {C_6}{H_4} - OH + NaHC{O_3} \to p - {N_2}O - {C_6}{H_4} - ONa + C{O_2} + {H_2}O$
So, when p-nitrophenol reacts with $NaHC{O_3}$ , it also evolves out carbon dioxide gas $C{O_2}$ .
Therefore, from the above equations, we can see that our correct option is D.
Here, in p-nitrophenol , p means para position i.e. nitro group is attached to the phenol at the para position.

Note:
Sodium bi carbonate is a very useful compound, especially in treating high acidic conditions. Sodium bi carbonate dissolves as sodium ions and the bicarbonate ions and provides the alkaline environment, thus, reducing the acidic conditions. It is often used to treat heartburns or used as an antacid.