When aqueous solution of benzene diazoniumchloride is boiled... | Chemistry | SolveeIt

Question

When aqueous solution of benzene diazoniumchloride is boiled, the product formed is

${C_6H_5CH_2OH}$

${C_6H_6 + N_2}$

${C_6H_5COOH}$

${C_6H_5OH}$

Answer

${C_6H_5OH}$

Explanation

Solution

When an aqueous solution of benzene diazonium chloride ( ${C_6H_5N_2Cl}$ ) is boiled, it undergoes a reaction known as "benzene diazonium chloride decomposition" or "diazotization." The main product formed is phenol ( ${C_6H_5OH}$ ) along with the evolution of nitrogen gas ( ${N_2}$ ). The reaction can be represented as follows:

${C_6H_5N_2Cl}$ (benzene diazonium chloride) + ${H_2O}$ (water) ${\rightarrow}$ ${C_6H_5OH}$ (phenol) + ${N_2}$ (nitrogen gas) + ${HCl}$ (hydrochloric acid)

So the products formed are ${C_6H_5OH}$ (phenol) and ${N_2}$ (nitrogen gas).

So the correct answer is option (D): ${C_6H_5OH}$

Chemistry Question on Alcohols, Phenols and Ethers

Solution