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Question: When an oscillator completes \(100\)oscillations, its amplitude reduces to \(\dfrac{1}{3}\)of its in...

When an oscillator completes 100100oscillations, its amplitude reduces to 13\dfrac{1}{3}of its initial value. What will be its amplitude when it completes 200200oscillations?
A. 18\dfrac{1}{8}
B. 23\dfrac{2}{3}
C. 16\dfrac{1}{6}
D. 19\dfrac{1}{9}

Explanation

Solution

In this question, we need to determine the amplitude of the oscillator when it completes 200 oscillations such that when it completes 100 oscillations, its amplitude reduces to 13\dfrac{1}{3} of its initial value. For this, we will use the fact that for damped oscillation, the amplitude after time `t’ is given by A=A0ebtA = {A_0}{e^{ - bt}}.

Complete step by step answer:
This is a case of damped oscillation. In damped oscillation, the amplitude of the particle decreases exponentially with respect to time. If the particle at the time t=0t = 0has its amplitude A0{A_0}and after time t its amplitude becomes A,
Then, A=A0ebt..........(i)A = {A_0}{e^{ - bt}}..........\left( i \right)
Where b is damping constant from the given question,
Case (i): When an oscillator completes 100100oscillations, i.e., at the time t=100Tt = 100Tthe amplitude reduces to 13\dfrac{1}{3}of its initial value i.e. A=A03,A = \dfrac{{{A_0}}}{3},
So, from the equation A=A0ebtA = {A_0}\,\,\,\,{e^{ - bt}} , we have
A03=AOeb(100T)\Rightarrow \dfrac{{{A_0}}}{3} = {A_O}\,\,\,{e^{ - b\left( {100T} \right)}}
e100T=13..........(ii)\Rightarrow {e^{ - 100T}} = \dfrac{1}{3}..........\left( {ii} \right)
Case (ii): When the particle completes 200200oscillation, i.e., t=200Tt = 200Tthen, the amplitude==?
Let the new amplitude be A then from equation (i),

A=A0ebt A=A0eb(200T) A=A0[eb(100T)]2...........(iii) \Rightarrow A = {A_0}\,\,{e^{ - bt}} \\\ \Rightarrow A = {A_0}\,\,{e^{ - b\left( {200T} \right)}} \\\ \Rightarrow A = {A_0}{\left[ {{e^{ - b\left( {100T} \right)}}} \right]^2}...........\left( {iii} \right) \\\

Now, from equation (ii) and (iii), we have
A=A0[13]2=A0×19 A=A09  \Rightarrow A = {A_0}{\left[ {\dfrac{1}{3}} \right]^2} = {A_0} \times \dfrac{1}{9} \\\ \Rightarrow A = \dfrac{{{A_0}}}{9} \\\
So, the amplitude will become 19\dfrac{1}{9}of its initial value.
Hence, the correct option is (D).

Note: The force applied into the particle during damping oscillations is given by F=kxbvF = - kx - bv, and the differential equation for it is given by d2xdt2+6mdxdt+kmn=0\dfrac{{{d^2}x}}{{d{t^2}}} + \dfrac{6}{m}\,\,\dfrac{{dx}}{{dt}} + \dfrac{k}{m}n = 0. The damped oscillation means an oscillation that fades away with time. For example, a swinging pendulum, weight on spring in a resistor – inductor-capacitor (RLC) circuit.