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Question: When an object is placed \(20\,cm\) from a complex lens then a real image is formed \(30\,cm\) from ...

When an object is placed 20cm20\,cm from a complex lens then a real image is formed 30cm30\,cm from the lens. Where should the object be placed so that a real image of the same size is formed by the lens.
A. Object should be placed 24cm24\,cm from the lens
B. Object should be placed 34cm34\,cm from the lens
C. Object should be placed 14cm14\,cm from the lens
D. Object should be placed 30cm30\,cm from the lens

Explanation

Solution

In order to solve this question, you must be aware about the relationship between the distance of an image (v), the distance of an object (u), and the focal length (f) of the lens. This is given by a formula known as Lens formula. It is applicable for convex as well as concave lenses.

Complete step by step answer:
It is given that, when u=20u = - 20 cm v=30v = 30 cm
We know that;
1v1u=1f\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f} (Lens formula)
1f=130120\dfrac{1}{f} = \dfrac{1}{{30}} - \dfrac{1}{{ - 20}}
We get, f=12f = 12 cm
Now, m=1m = - 1(Image formed is of the same size as that of the object)
vu=1\dfrac{v}{u} = - 1
v=uv = - u
Using lens formula,
112=1u1u\dfrac{1}{{12}} = \dfrac{1}{{ - u}} - \dfrac{1}{u}
u=24\therefore u = - 24 cm
Therefore, the object should be placed 24 cm from the lens.

Hence, option A is correct.

Note: A convex lens is employed in microscopes and magnifying glasses to converge all incoming light rays to a particular point. It is also used in cameras. The various types of lenses are also used in the correction of certain defects of the eye.