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Question: When an input signal \[1\] is applied to a NOT gate, its output is: A) \[1\] B) \[0\] C) Eithe...

When an input signal 11 is applied to a NOT gate, its output is:
A) 11
B) 00
C) Either 00 or 11
D) Both 00 and 11

Explanation

Solution

NOT gate is one of the basic logical gates. It can be remembered from the name itself that NOT implies getting the opposite output. Remember all the basic gates to avoid confusion.

Complete step by step solution:
The various basic logic gates used digital systems are as follows:
1. OR Gate
2. AND Gate
3. NOT Gate
4. XOR Gate
Below is the NOT gate.

OR GATE: In OR gate the output of an OR gate gives the state 11 , if one or more inputs attain the state 11 i.e. when any one input is 11 then the output will be one.
The Boolean expression of the OR gate is given as Y=A+BY=A+B, which is read as YY equals AAORORBB.

AND GATE: In AND gate the output of an AND gate is 11 if and only if all the inputs are in state 11. The Boolean expression of AND gate is Y=A.BY=A.B which is read as Y equals A ‘AND’ B.

NOT GATE: In NOT gate the output of a NOT gate attains the state 11 if and only if the input does not attain the state 11 . The Boolean expression is Y=AY=\overline{A} , read as Y equals NOT A.

Hence for input signal 11 the output will be 00.

Note: All basic gates must be remembered. NAND and XNOR gates are the logical gates which can be obtained using the basic OR, NOT and AND gate. Also the truth table can be easily constructed for each logical gate based on the above definitions. Truth tables make it easier to understand logical gates.