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Question: When an ideal gas in a cylinder was compressed isothermally by a piston, the work done on the gas wa...

When an ideal gas in a cylinder was compressed isothermally by a piston, the work done on the gas was found to be 1.5×1046mujoules1.5 \times 10^{4}\mspace{6mu} joules. During this process about

A

3.6×1033.6 \times 10^{3} cal of heat flowed out from the gas

B

3.6×1033.6 \times 10^{3} cal of heat flowed into the gas

C

1.5×1041.5 \times 10^{4} cal of heat flowed into the gas

D

1.5×1041.5 \times 10^{4} cal of heat flowed out from the gas

Answer

3.6×1033.6 \times 10^{3} cal of heat flowed out from the gas

Explanation

Solution

In isothermal compression, there is always an increase of heat. which must flow out the gas.

ΔQ=ΔU+ΔWΔQ=ΔW6mu6mu(6muΔU=0)\Delta Q = \Delta U + \Delta W \Rightarrow \Delta Q = \Delta W\mspace{6mu}\mspace{6mu}(\because\mspace{6mu}\Delta U = 0)

ΔQ=1.5×104J=1.5×1044.18cal=3.6×103cal\Delta Q = - 1.5 \times 10^{4}J = \frac{1.5 \times 10^{4}}{4.18}cal = - 3.6 \times 10^{3}cal