When ammonia is heated with cupric oxide, a molecule of ammo... | Chemistry | SolveeIt

When ammonia is heated with cupric oxide, a molecule of ammomia will

Gain 3 electrons

Lose 3 electrons

Gain 2 electrons

Lose 2 electrons

Answer

Lose 3 electrons

Explanation

${2NH_3 + 3CuO -> N2 + H20 + 3Cu }$ ${2NH3 -> N_2}$ (O.S. = -3) (O.S. = 0) Thus each N atom (or each $NH_3$ molecule) loses 3 electrons.

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