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Question: When ammonia hydroxide is added to solution \(B\) , a pale blue precipitate is formed. This pale blu...

When ammonia hydroxide is added to solution BB , a pale blue precipitate is formed. This pale blue precipitate dissolves in excess ammonium hydroxide giving an inky blue solution. What is the cation [positive ion] present in solution BB ? What is the probable colour of solution BB .

Explanation

Solution

When ammonia hydroxide reacts with a solution of copper sulphate and copper hydroxide is produced in the product which is blue pale in colour. Copper hydroxide is having Cu2+C{u^{2 + }} cations in it.

Complete answer:
In this question, the chemical formula of ammonia hydroxide can be written as NH4OHN{H_4}OH . Ammonia hydroxide is a dark blue solution. As it is given that when this ammonia hydroxide NH4OHN{H_4}OH reacts with a solution BB , then a pale blue precipitate is formed. As we know that when we react ammonia hydroxide NH4OHN{H_4}OH with the solution of copper sulphate CuSO4CuS{O_4} which is having chemical formula as then the product obtained is then copper hydroxide Cu(OH)2Cu{(OH)_2} and copper sulphate is obtained in the product.
This reaction can be represented as follows:
2NH4OH+CuSO4Cu(OH)2+(NH4)2SO42N{H_4}OH + CuS{O_4} \to Cu{(OH)_2} + {(N{H_4})_2}S{O_4}
[Pale blue]
Here, we can see that in this reaction the solution BB is Copper sulphate CuSO4CuS{O_4} solution and in the product, it is copper hydroxide Cu(OH)2Cu{(OH)_2} that is a pale blue coloured precipitate.
In the second part of the question, it is given that when the above formed pale blue precipitate reacts with excess ammonium hydroxide then it gives an inky blue solution. Therefore, it means that when precipitate of Copper hydroxide Cu(OH)2Cu{(OH)_2} reacts with excess ammonium hydroxide then it forms tetra amine copper [II][II] sulphate which is a deep blue soluble complex salt and have the chemical formulas as [Cu(NH3)4]SO4[Cu{(N{H_3})_4}]S{O_4} .
This reaction can be represented as:
Cu(OH)2+(NH4)2SO4+2NH4OH[Cu(NH3)4]SO4+4H2OCu{(OH)_2} + {(N{H_4})_2}S{O_4} + 2N{H_4}OH \to [Cu{(N{H_3})_4}]S{O_4} + 4H{ _2}O
Therefore, the required solution BB is copper hydroxide Cu(OH)2Cu{(OH)_2} and also, we know that in copper hydroxide the copper has +2 + 2 charge. Therefore, copper sulphate has Cu2+C{u^{2 + }} cation in it.

Note:
Ammonia hydroxide NH4OHN{H_4}OH is a dark blue coloured compound and when it reacts with copper sulphate CuSO4CuS{O_4} then it converts the colour of the solution into pale blue in the form of copper hydroxide Cu(OH)2Cu{(OH)_2} .