Question
Chemistry Question on d -and f -Block Elements
When alkaline KMnO4 is treated with KI, the Iodide ion is oxidized to________.
A
IO-
B
I2
C
IO3-
D
IO4-
Answer
IO3-
Explanation
Solution
The correct answer is option (C): IO3-
5KI+2KMnO₄ +H₂O → 5KIO₃ +2MnO₂ +6KOH In this reaction, KI reduces potassium permanganate to manganese dioxide (MnO2). A KI is getting oxidized to potassium iodate. The oxygen is transferred from permanganate ions to iodine ions, thus resulting in the formation of iodate ions.