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Question: When acetamide is treated with \(NaOBr\), the product formed is : A) \(C{H_3}CN\) B) \(C{H_3}C{...

When acetamide is treated with NaOBrNaOBr, the product formed is :
A) CH3CNC{H_3}CN
B) CH3CH2NH2C{H_3}C{H_2}N{H_2}
C) CH3NH2C{H_3}N{H_2}
D) None of these

Explanation

Solution

This reaction of acetamide with NaOBrNaOBr is an example of Hofmann degradation of primary amides to amines with resultant compounds having one carbon atom less. It is an important method of preparation of amines and this reaction is also used to descend the series as the product amine contains one less carbon atom.

Complete step by step answer: As the name of the reaction suggests, Hoffmann bromamide degradation was given by August Von Hoffmann. It is also called the Hofmann rearrangement reaction.
So, understand complete meaning of Hoffmann bromamide synthesis
Hoffmann is the chemist name who proposed this mechanism.
Bromamide is a Bromine molecule and amide is used in the reaction.
Degradation – The one carbon is lesser in the product compared to reactant, so that degradation of product takes place.
NaOBrNaOBr is a compound and its chemical name is Sodium hypobromite.
Acetamide reacts with NaOBrNaOBr and gives methylamine. This reaction is also called as Hoffmann Bromamide synthesis


Step -11 In the above reaction the Acetamide first reacts with Sodium hypobromite and forms N-bromo-acetamide by the abstracting proton from the compound and forms a conjugate base. This conjugate base is called a bromamide.
Step -22 In this step sodium hydroxide reacts with bromamide and another hydrogen is removed and CH3−CO−NBrC{H_3} - CO - NBr is left behind.
Step -33 In this step the Bromine is eliminated as Bromide ion and in this step the alkyl group is directly attached to the Nitrogen atom and forms directly methyl isocyanate.
Step -44 In this step Isocyanate reacts with water and removal of carbon dioxide takes place and forms methyl amine.
So, the first option name is methyl cyanide; it is not the answer.
Coming to the second option, its name is Ethyl amine.
Third option is Methylamine.
Hence the answer is (c) Methylamine.

Note: Sometimes this reaction actually uses Bromine and sodium hydroxide, but Sodium hypobromite is also equivalent with Bromine and Sodium hydroxide. This reaction proceeds with the formation of isocyanate intermediate.