Solveeit Logo

Question

Question: When a spring is stretched by 2 cm, it stores 100 J of energy. If it is stretched further by 2 cm, t...

When a spring is stretched by 2 cm, it stores 100 J of energy. If it is stretched further by 2 cm, the stored energy will be increased by

A

100 J

B

200 J

C

300 J

D

400 J

Answer

300 J

Explanation

Solution

100=12kx2100 = \frac { 1 } { 2 } k x ^ { 2 } (given)

W=12k(x22x12)=12k[(2x)2x2]W = \frac { 1 } { 2 } k \left( x _ { 2 } ^ { 2 } - x _ { 1 } ^ { 2 } \right) = \frac { 1 } { 2 } k \left[ ( 2 x ) ^ { 2 } - x ^ { 2 } \right]