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Question

Physics Question on Stress and Strain

When a rod is heated but prevented from expanding the stress developed is independent of:

A

material of the rod

B

rise in temperature

C

length of rod

D

none of the above

Answer

length of rod

Explanation

Solution

Lt=L0(1+αΔθ)L_{t}=L_{0}(1+\alpha \Delta \theta)
ΔL=LtL0=L0αΔθ(i)\Delta L=L_{t}-L_{0}=L_{0}\, \alpha \,\Delta \theta \ldots( i )
If the same rod of length Lo is subjected to stress along its length, then extension in length can be calculated by Hooke's law.
Y= tress  strain = stress ΔL/L0Y=\frac{\text { tress }}{\text { strain }}=\frac{\text { stress }}{\Delta L / L_{0}}
=L0× stress ΔL=\frac{L_{0} \times \text { stress }}{\Delta L}
ΔL=L0×stressY...(ii)\therefore \Delta L=\frac{L_{0} \times \text{stress}}{Y} ...(ii)
If the rod is prevented by expanding, we have
L0αΔθ=L0× stress YL_{0} \alpha \Delta \theta=\frac{L_{0} \times \text { stress }}{Y}
\therefore Stress =YαΔθ=Y \alpha \Delta \theta
(independent of L0)\left.L_{0}\right)