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Question

Physics Question on Centre of mass

When a ring is rolling V1,V2,V3,V4V_1, V_2, V_3, V_4 are velocities of top most point, lowest point, end point of horizontal diameter, center of ring respectively. The decreasing order of these velocities is

A

V2,V1,V4,V3V_2, V_1, V_4, V_3

B

V2,V1,V3,V4V_2, V_1, V_3, V_4

C

V1,V2,V3,V4V_1, V_2, V_3, V_4

D

V1,V3,V4,V2V_1, V_3, V_4, V_2

Answer

V1,V3,V4,V2V_1, V_3, V_4, V_2

Explanation

Solution

Let velocity of centre =V0 V4=V0 V1=2V0 V2=0 V3=2V0 V1>V3>V4>V2\begin{array}{l} = V _{0} \\\ V _{4}= V _{0} \\\ V _{1}=2 V _{0} \\\ V _{2}=0 \\\ V _{3}=\sqrt{2} V _{0} \\\ \therefore V _{1}> V _{3}> V _{4}> V _{2} \end{array}