Question

When a proton is accelerated through 1V, then its kinetic energy will be

• A. 1840 eV
• B. 13.6 eV
• C. 1 eV
• D. 0.54 eV

Answer 1

Answer: (C)

1 eV

Answer 2

$\Delta KE = qV = eV = e \times 1 = 1eV$