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Question: When a piece of aluminum wire of finite length is drawn through a series of dies to reduce its diame...

When a piece of aluminum wire of finite length is drawn through a series of dies to reduce its diameter to half its original value, its resistance will become:-
A) Two times
B) Four times
C) Eight times
D) Sixteen times

Explanation

Solution

Resistance of a wire is directly proportional to its length and inversely related to its area. While drawing a wire, its volume and resistivity remain constant. This principle can be used here. Convert the resistance equation in terms of volume. The area of a wire is proportional to the square of its diameter. When the diameter is reduced to half, the area of the wire changes, thereby its resistance also changes.
Formula used:
V=AlV=Al
R=ρlAR=\rho \dfrac{l}{A}
A=πr2=π(d2)2A=\pi {{r}^{2}}=\pi {{\left( \dfrac{d}{2} \right)}^{2}}

Complete step-by-step solution:
Electrical resistance R of a wire is directly proportional to its length ll and inversely proportional to its cross-sectional area AA. Also, it depends on the material with which the wire is made (specific electrical resistance or resistivity ρ\rho ).
Resistance,R=ρlAR=\rho \dfrac{l}{A} -------- 1
While stretching a conductor, its resistivity and the total volume (V) remains constant.
Convert equation 1 in terms of volume, by multiplying numerator and denominator with area A. Then,
R=ρl×AA×A=ρVA2\Rightarrow R=\dfrac{\rho l\times A}{A\times A}=\dfrac{\rho V}{{{A}^{2}}}
(V=AlV=Al)
From the above equation, we can see that,
R1A2\Rightarrow R\propto \dfrac{1}{{{A}^{2}}}
We have,
A=πr2=π(d2)2A=\pi {{r}^{2}}=\pi {{\left( \dfrac{d}{2} \right)}^{2}}
Ad2\Rightarrow A\propto {{d}^{2}}
Then,
R1d4\Rightarrow R\propto \dfrac{1}{{{d}^{4}}}
Hence, if we reduce the diameter to half,
R1(d2)4\Rightarrow R'\propto \dfrac{1}{{{\left( \dfrac{d}{2} \right)}^{4}}}
RR increases to 16R16R.
The answer is option D

Note: The resistance of an object depends on its shape and the material with which it is composed. The resistivity of a material is dependent upon the electronic structure of the material and its temperature. For most of the materials, resistivity increases with increasing temperature. But, in the case of conductors, the resistivity increases with increasing temperature. Since the atoms vibrate more rapidly over larger distances at higher temperatures, the moving electrons through a metal make more collisions, and its resistivity increases.