Question

When a picture drawn on paper is seen through a slab of a transparent material of thickness 5 cm, it appears to be raised by 1.5 cm. Critical angle at the boundary of this transparent material and air is –

• A. sin^–1$\left( \frac { 2 } { 3 } \right)$
• B. sin^–1$\left( \frac { 5 } { 7 } \right)$
• C. sin^–1$\left( \frac { 6 } { 11 } \right)$
• D. sin^–1$\left( \frac { 7 } { 10 } \right)$

Answer 1

Answer: (D)

sin^–1$\left( \frac { 7 } { 10 } \right)$

Answer 2

s =

m =

q_c = sin^–1 $\left( \frac { 1 } { \mu } \right)$ = sin^–1$\left( \frac { 7 } { 10 } \right)$