Question

When a particle executes Simple Harmonic Motion, the nature of graph of velocity as a function of displacement will be :

• A. Circular
• B. Elliptical
• C. Sinusoidal
• D. Straight line

Answer 1

Answer: (B)

Elliptical

Answer 2

Let, $x = A\ sin ωt$
$v = Aωt\ cos ωt$
$v=±ω\sqrt {A^2−x^2}$
$\frac {v^2}{ω^2}+x^2=A^2$
$⇒$ Nature of graph will be Ellipse.

So, the correct option is (B): Elliptical.