Question
Physics Question on Photoelectric Effect
When a metal surface is illuminated by light of wavelengths 400nm and 250nm, the maximum velocities of the photoelectrons ejected are V and 2V respectively. The work function of the metal is
A
2hc×106J
B
1.5hc×106J
C
hc×106J
D
0.5hc×106J
Answer
2hc×106J
Explanation
Solution
Let the work function of metal be W,
Case 1,200nmhc−2W=mv2...1
Case 2,250nmhc−W=2mv2...2
From 1 and 2,
⇒200nmhc−2W=2−W+500nmhc
⇒2w−2W=hc(2001−5001)nm1
23W=hc(1000300)×109
⇒W=hc32×10003×106
⇒W=2hc×106J