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Question

Physics Question on Photoelectric Effect

When a metal surface is illuminated by light of wavelengths 400nm400\, nm and 250nm250\,nm, the maximum velocities of the photoelectrons ejected are VV and 2V2 V respectively. The work function of the metal is

A

2hc×106J2 h c \times 10^{6}\, J

B

1.5hc×106J1.5 hc \times 10^{6} \,J

C

hc×106Jhc \times 10^{6}\, J

D

0.5hc×106J0.5 hc \times 10^{6} \,J

Answer

2hc×106J2 h c \times 10^{6}\, J

Explanation

Solution

Let the work function of metal be W,
Case 1,hc200nm2W=mv2...11, \frac{ hc }{200\, nm }-2 W = mv ^{2}...1
Case 2,hc250nmW=2mv2...22, \frac{ hc }{250 \,nm }- W =2 mv ^{2}...2
From 1 and 2,
hc200nm2W=W2+hc500nm\Rightarrow \frac{ hc }{200 \,nm }-2 W =\frac{- W }{2}+\frac{ hc }{500 \,nm }
2wW2=hc(12001500)1nm\Rightarrow 2 w -\frac{ W }{2}= hc \left(\frac{1}{200}-\frac{1}{500}\right) \frac{1}{ nm }
3W2=hc(3001000)×109\frac{3 W }{2}= hc \left(\frac{300}{1000}\right) \times 10^{9}
W=hc23×31000×106\Rightarrow W = hc \frac{2}{3} \times \frac{3}{1000} \times 10^{6}
W=2hc×106J\Rightarrow W =2 hc \times 10^{6}\, J