Question

When a magnet is suspended at an angle 30⁰ from the magnetic meridian, it makes an angle 45ŗ with horizontal. What will be the actual angle of dip?

• A. tan^–1$\left( \frac { \sqrt { 3 } } { 2 } \right)$
• B. tan^–1$( \sqrt { 3 } )$
• C. 45⁰
• D. 30⁰

Answer 1

Answer: (A)

tan^–1$\left( \frac { \sqrt { 3 } } { 2 } \right)$

Answer 2

tan φ′ = $\frac { \tan \phi } { \cos 30 ^ { \circ } }$

φ = tan^–1$\left( \frac { \sqrt { 3 } } { 2 } \right)$