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Question

Physics Question on mechanical properties of solids

When a long spring is stretched by 2 cm, its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be:

A

U5\frac {U}{5}

B

5U5U

C

10U10U

D

25U25U

Answer

25U25U

Explanation

Solution

U=12K(2)2U = \frac 12K(2)^2
U=2KU = 2K
U=12K(10)2U' = \frac 12K(10)^2
U=50KU' = 50K
U=25 . 2KU' = 25\ . \ 2K
U=25UU' = 25U

So, thew correct option is (D): 25U